(2x-4)(1/3x^2-4/3x-4)=0

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Solution for (2x-4)(1/3x^2-4/3x-4)=0 equation: 


x in (-oo:+oo)

(2*x-4)*((1/3)*x^2-((4/3)*x)-4) = 0

(2*x-4)*((1/3)*x^2+(-4/3)*x-4) = 0

(2*x-4)*(1/3*x^2-4/3*x-4) = 0

1/3*x^2-4/3*x-4 = 0

1/3*x^2-4/3*x-4 = 0

DELTA = (-4/3)^2-(-4*1/3*4)

DELTA = 64/9

DELTA > 0

x = ((64/9)^(1/2)+4/3)/(1/3*2) or x = (4/3-(64/9)^(1/2))/(1/3*2)

x = 6 or x = -2

(x+2)*(x-6) = 0

(2*x-4)*(x+2)*(x-6) = 0

( 2*x-4 )

2*x-4 = 0 // + 4

2*x = 4 // : 2

x = 4/2

x = 2

( x+2 )

x+2 = 0 // - 2

x = -2

( x-6 )

x-6 = 0 // + 6

x = 6

x in { 2, -2, 6 }

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